What My Research Assistant Gets Up To When I’m Out of Town

4 Responses to What My Research Assistant Gets Up To When I’m Out of Town

1. Pingback: Barsk

2. Pingback: Barsk

3. wdb says:

   August 16, 2004 at 2:58 pm

   I believe your calculation should read negative 40.77 and not positive 40.78. in the following equation

   500g EtOH/46gmol^-1 = 10.87mol EtOH/0.5kg H20 = 21.74 * -1.86 = -40.43C * 1.8 + 32 = 40.78

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4. Barsk says:

   August 16, 2004 at 6:53 pm

   Thanks for pointing out my typos, however I think that the meaning of it was quite clear.

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